CH4 + 2O2 → CO2 + 2H2O If you change the 2 in front of 2O2 to 3, what will be the change in the results on the right side of the equation?
There are now molecules of 3H2O. <-? Nothing changes in the equation. There are now 3 molecules of CO2. <-? There remains an additional molecule of O2. Unit test of simple chemical reactions 1. There is one extra molecule of O2 left.
2. Covalent bonds tend to be less polar than ionic bonds.
3.PH3
4. replacement
5. Each carbon atom would share one pair of electrons with hydrogen and three pairs with the other carbon atom.
6. H2SO4 + 8HI → H2S + 4I2 + 4H2O
7.2, 1, 2
8. Nitrogen and oxygen have an electronegativity difference of 0.5, so the bond is polar covalent, with oxygen attracting electrons to it.
9. Sodium donates an electron to chlorine.
10. Selenium (Se)
11. bond type
12. six
13.K
14. indicator
the rest are essay questions sorry :/ yes, he is right. just took the test. Yes sir, they are right. You’ve taken the test and you’re sure they’re correct, aren’t you? Thanksuuuuu always correct my guy is a scary potato the potato is not known Does anyone know essay questions? (ALL CREDIT TO THE BRAINLY POST :>)
The bonding activity that occurs between phosphorus and chlorine is the covalent bond
Covalent bond is an interaction between two atomic elements that share electrons with each other.
In phosphorus pentachlor PCl₅, a covalent bond occurs between phosphorus and chlorine.
This is because phosphorus is the central atom which is attached to 5 different chlorine atoms, each chlorine atom needs one electron each to complete its octet rule and since phosphorus has five valence electrons in its shell the outermost, it shares it with each of the chlorine atoms. atoms. Thank you Mr. Sus Patate…! @potato is 100% correct Crazy question. Let’s look at each answer.
1. It unbalances. H is not balanced. O is not balanced.
2. Obviously not a good answer. Always unbalanced.
3. Always unbalanced. C and H balanced.
4. must be correct since the other possibilities are not correct. You have added 1 O2, so some will remain.