At standard temperature, a gas has a volume of 275mL. The temperature is then increased to 130. Celsius, and the pressure is kept constant. What’s the new volume? How can I work this?
v1 = 275mL
t1 = 130.C or 403K
v2=???
t2 = ???
Can anyone help me please? The answer is 406 mL The problem lists gas at the standard temperature which is 273 K. So T1 is 273, T2 is 403, V1 = 275 and you solve for V2. Note the correct spelling of celsius. show the elaboration V2= V1T2/T1
=(0.28L)(403.15K)/(273.15K)
=0.41L You know that STP stands for “standard temperature and pressure”. The T norm is 273 and the P norm is 1 atm or 760 mm Hg. Ahh I got it. So the standard temperature is always 273 k? Well… Some in the world have different standards.
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