1.You are driving at a speed of 28.7m/s (64.2138mph) when suddenly the car
in front of you (previously traveling together
speed) brakes. Considering an average human
reaction, you hit the brakes 0.427s later.
Suppose the brakes of both cars are completely
engaged and the coefficient of friction is
0.705 between the two cars and the road.
The acceleration of gravity is 9.8 m/s2.
Calculate the magnitude of the acceleration
of the car in front of you when it brakes.
Response in units of m/s2.
2.Calculate the braking distance of the car by
in front of you.
Answer in units of m.
3.Find the minimum safe distance at which you
can follow the car in front of you and avoid
hitting it (in the event of emergency braking
described here).
Answer in units of m.
Please help! I do not understand ! a = -mu g = -.705*9.8 = -6.91 m/s^2
v = Vi + to
0 = 28.7 – 6.91t
t = 4.15 seconds to stop
d = average speed * 4.15
= 28.7/2 * 4.15 = 59.6 meters
it stops at 59.6 meters
we stop in 59.6 + .427 * 28.7 meters
so we better be .427*28.7=12.3 yards behind or we hit him right before he stops nvm im dum how did you find the time where did you get .427???