in a binomial distribution with 6 independent trials, the probabilities of 3 and 4 successes are found to be 0.2457 and 0.0819 respectively. find the parameter p of the binomial? 4/13 5/9 4/9 8/13?,Welcome to the solution site, which is interested in answering educational questions, as it provides an answer to your questions in all areas
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in a binomial distribution with 6 independent trials, the probabilities of 3 and 4 successes are found to be 0.2457 and 0.0819 respectively. find the parameter p of the binomial? 4/13 5/9 4/9 8/13
answer : WTMedium Open in App Solution Verified by Toppr
Correct option is C)
In a binomial distribution consisting of 5 independent trials, n = 5
The probability of 1 and 2 successes are 0.4096 and 0.2048 respectively.
5 C 1 p 1 (1−p) 5−1 =0.4096 5 C 2 p 2 (1−p) 5−2 =0.2048 5p(1−p) 4
=0.4096 _____ (1) 10p
2 (1−p) 3 =0.2048 ______ (2)
Divide equation (1) by (2), we get
2p (1−p) =2 5p=1 p= 5 1
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