a brick falls from the roof of a building. Going down, it passes a 2 m high window and we observe that it goes from the top to the bottom of the window in 0.25 s. (a) How fast was it moving when it passed the top of the window? (b) How far below the roof of the building is the top of the window? medium speed overtaking window
= -2 meters/0.25s = -8ms
constant acceleration = -9.81 m/s
then crossing the window
v = Vi-.981t
change of v crossing the window = -9.81*.25 = -2.4525 m/s
half = -1.23 m/s
so v at the top of the window
= -8+1.23 = -6.77 m/s
so how far did it fall from the roof to the top of the window?
v = 0 -9.81t
-6.77 = -9.81t
t = 0.69 seconds
d = 0.49 t^2
=.233 yards TY lot Damon last two rows
d = 4.9 t^2
= 2.33 meters