Consider a class with 10 sophomores, 8 juniors, and 6 seniors. Two students are drawn. 1) What is the probability of selecting 1 junior and 1 senior.
2) Find the odds of selecting two students who are not seniors.
How can I configure them to solve?
Any help is greatly appreciated!! the total number of students is 24.
Probability of 1 junior and 1 senior are..
Pr=(8/24)(6/23)
The second:
Pr=(18/24)(17/23)
Notice that in each, the numerator is the number of possible paths to success, the denominator is the number of possible paths. For number one there is a total of 24 students when you add 10 + 8 + 6. Then you want to find 1 junior and 1 senior which when added together becomes 2. soo….
2/24 = 1/12 reduced! 🙂