Which element would most likely lose electrons to form positive ions when bonding with other elements? A: Gallium (Ga)
B: Rubidium (Rb)
C: Iodine (I)
D: Argon (Ar) 1) rubidium (Rb)
2) The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.
3) nitrogen (N) and oxygen (O)
4) the relative strength with which an element attracts electrons into a chemical bond
5) bromine and rubidium nitrogen (Rb)
The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.
nitrogen (N) and oxygen (O)
the relative strength with which an element attracts electrons into a chemical bond
bromine and nitrogen
100% correct no one is 100% correct!!! @nobody. I could kiss you RN 😉 i hate furries that's ok tysmmm BTW @ no one is 1000000000000% correct Thanks! lol how ironic that a furry used furry haters answers to check theirs and it was 100% Ga has 31 protons and is a group IIIA metal from the table, forms +3 ion by losing 3 electrons thanks to both of you Gallium is a good answer and for the reason given.
However, I think Rb is a better answer since the question asks for the "most likely". Rb is much more reactive than Ga. If for no other reason Rb has only one electron to lose while Ga has three to lose and the ionization potential of Rb (with one electron) is less than that of Ga (with three electrons). .